ida 分析 发现是铭文比较 利用输入当作 idx在data里面查找字符进行比较，

可以直接 脚本

EXP

v4 = [0 for i in range(12)]
v4[0] = '*';
v4[1] = 'F';
v4[2] = '\\'';
v4[3] = '"';
v4[4] = 'N';
v4[5] = ',';
v4[6] = '"';
v4[7] = '(';
v4[8] = 'I';
v4[9] = '?';
v4[10] = '+';
v4[11] = '@';

data = [0x7E, 0x7D, 0x7C, 0x7B, 0x7A, 0x79, 0x78, 0x77, 0x76, 0x75, 
  0x74, 0x73, 0x72, 0x71, 0x70, 0x6F, 0x6E, 0x6D, 0x6C, 0x6B, 
  0x6A, 0x69, 0x68, 0x67, 0x66, 0x65, 0x64, 0x63, 0x62, 0x61, 
  0x60, 0x5F, 0x5E, 0x5D, 0x5C, 0x5B, 0x5A, 0x59, 0x58, 0x57, 
  0x56, 0x55, 0x54, 0x53, 0x52, 0x51, 0x50, 0x4F, 0x4E, 0x4D, 
  0x4C, 0x4B, 0x4A, 0x49, 0x48, 0x47, 0x46, 0x45, 0x44, 0x43, 
  0x42, 0x41, 0x40, 0x3F, 0x3E, 0x3D, 0x3C, 0x3B, 0x3A, 0x39, 
  0x38, 0x37, 0x36, 0x35, 0x34, 0x33, 0x32, 0x31, 0x30, 0x2F, 
  0x2E, 0x2D, 0x2C, 0x2B, 0x2A, 0x29, 0x28, 0x27, 0x26, 0x25, 
  0x24, 0x23, 0x20, 0x21, 0x22]
flag = ""
for i in v4:
    flag += chr(data.index(ord(i))+1)
print flag

# U9X_1S_W6@T?